e04kz Method
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e04kz is an easy-to-use modified Newton algorithm for finding a minimum of a function Fx1,x2,,xn, subject to fixed upper and lower bounds on the independent variables x1,x2,,xn, when first derivatives of F are available. It is intended for functions which are continuous and which have continuous first and second derivatives (although it will usually work even if the derivatives have occasional discontinuities).

Syntax

C#
public static void e04kz(
	int n,
	int ibound,
	E04..::.E04KZ_FUNCT2 funct2,
	double[] bl,
	double[] bu,
	double[] x,
	out double f,
	double[] g,
	out int ifail
)
Visual Basic (Declaration)
Public Shared Sub e04kz ( _
	n As Integer, _
	ibound As Integer, _
	funct2 As E04..::.E04KZ_FUNCT2, _
	bl As Double(), _
	bu As Double(), _
	x As Double(), _
	<OutAttribute> ByRef f As Double, _
	g As Double(), _
	<OutAttribute> ByRef ifail As Integer _
)
Visual C++
public:
static void e04kz(
	int n, 
	int ibound, 
	E04..::.E04KZ_FUNCT2^ funct2, 
	array<double>^ bl, 
	array<double>^ bu, 
	array<double>^ x, 
	[OutAttribute] double% f, 
	array<double>^ g, 
	[OutAttribute] int% ifail
)
F#
static member e04kz : 
        n:int * 
        ibound:int * 
        funct2:E04..::.E04KZ_FUNCT2 * 
        bl:float[] * 
        bu:float[] * 
        x:float[] * 
        f:float byref * 
        g:float[] * 
        ifail:int byref -> unit 

Parameters

n
Type: System..::.Int32
On entry: the number n of independent variables.
Constraint: n1.
ibound
Type: System..::.Int32
On entry: indicates whether the facility for dealing with bounds of special forms is to be used. It must be set to one of the following values:
ibound=0
If you are supplying all the lj and uj individually.
ibound=1
If there are no bounds on any xj.
ibound=2
If all the bounds are of the form 0xj.
ibound=3
If l1=l2==ln and u1=u2==un.
Constraint: 0ibound3.
funct2
Type: NagLibrary..::.E04..::.E04KZ_FUNCT2
You must supply this method to calculate the values of the function Fx and its first derivatives F xj  at any point x. It should be tested separately before being used in conjunction with e04kz (see E04 class).

A delegate of type E04KZ_FUNCT2.

bl
Type: array< System..::.Double >[]()[]
An array of size [n]
On entry: the lower bounds lj.
If ibound is set to 0, you must set bl[j-1] to lj, for j=1,2,,n. (If a lower bound is not specified for a particular xj, the corresponding bl[j-1] should be set to -106.)
If ibound is set to 3, you must set bl[0] to l1; e04kz will then set the remaining elements of bl equal to bl[0].
On exit: the lower bounds actually used by e04kz.
bu
Type: array< System..::.Double >[]()[]
An array of size [n]
On entry: the upper bounds uj.
If ibound is set to 0, you must set bu[j-1] to uj, for j=1,2,,n. (If an upper bound is not specified for a particular xj, the corresponding bu[j-1] should be set to 106.)
If ibound is set to 3, you must set bu[0] to u1; e04kz will then set the remaining elements of bu equal to bu[0].
On exit: the upper bounds actually used by e04kz.
x
Type: array< System..::.Double >[]()[]
An array of size [n]
On entry: x[j-1] must be set to a guess at the jth component of the position of the minimum, for j=1,2,,n. The method checks the gradient at the starting point, and is more likely to detect any error in your programming if the initial x[j-1] are nonzero and mutually distinct.
On exit: the lowest point found during the calculations of the position of the minimum.
f
Type: System..::.Double %
On exit: the value of Fx corresponding to the final point stored in x.
g
Type: array< System..::.Double >[]()[]
An array of size [n]
On exit: the value of F xj  corresponding to the final point stored in x, for j=1,2,,n; the value of g[j-1] for variables not on a bound should normally be close to zero.
ifail
Type: System..::.Int32 %
On exit: ifail=0 unless the method detects an error (see [Error Indicators and Warnings]).

Description

e04kz is applicable to problems of the form:
MinimizeFx1,x2,,xn  subject to  ljxjuj,  j=1,2,,n
when first derivatives are known.
Special provision is made for problems which actually have no bounds on the xj, problems which have only non-negativity bounds, and problems in which l1=l2==ln and u1=u2==un. You must supply a method to calculate the values of Fx and its first derivatives at any point x.
From a starting point you supplied there is generated, on the basis of estimates of the gradient of the curvature of Fx, a sequence of feasible points which is intended to converge to a local minimum of the constrained function.

References

Error Indicators and Warnings

Note: e04kz may return useful information for one or more of the following detected errors or warnings.
Errors or warnings detected by the method:
ifail=1
On entry,n<1,
oribound<0,
oribound>3,
oribound=0 and bl[j-1]>bu[j-1] for some j,
oribound=3 and bl[0]>bu[0],
ifail=2
ifail=3
The conditions for a minimum have not all been met but a lower point could not be found and the algorithm has failed.
ifail=4
Not used. (This value of the parameter is included to make the significance of ifail=5 etc. consistent in the easy-to-use methods.)
ifail=5
ifail=6
ifail=7
ifail=8
There is some doubt about whether the point x found by e04kz is a minimum. The degree of confidence in the result decreases as ifail increases. Thus, when ifail=5 it is probable that the final x gives a good estimate of the position of a minimum, but when ifail=8 it is very unlikely that the method has found a minimum.
ifail=9
ifail=10
It is very likely that you have made an error in forming the gradient.
ifail=-8000
ifail=-6000

Accuracy

Further Comments

The number of iterations required depends on the number of variables, the behaviour of Fx and the distance of the starting point from the solution. The number of operations performed in an iteration of e04kz is roughly proportional to n3+On2. In addition, each iteration makes at least m+1 calls of funct2 where m is the number of variables not fixed on bounds. So unless Fx and the gradient vector can be evaluated very quickly, the run time will be dominated by the time spent in funct2.
Ideally the problem should be scaled so that at the solution the value of Fx and the corresponding values of x1,x2,,xn are in the range -1,+1, and so that at points a unit distance away from the solution, F is approximately a unit value greater than at the minimum. It is unlikely that you will be able to follow these recommendations very closely, but it is worth trying (by guesswork), as sensible scaling will reduce the difficulty of the minimization problem, so that e04kz will take less computer time.

Example

See Also